Answer :
Let the given GP be a,ar,ar2,…
Sum of infinite GP is given by 
∴ According to the question
⇒ 
⇒ a = 3(1-r)
⇒ a =3-3r
⇒ a+3r = 3…(1)
⇒ 
⇒ the first term is a2 and the common ratio is r2.
∴ According to the question
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 2a = 3+3r
⇒ 2a-3r = 3…(2)
Equating 1 and 2 we get
a = 2 and r =1/3
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