Q. 4

If P(n): 2 × 4<su

for n=1,

2×42×1+1 + 33×1+1=2×43+34

= 2×64+81

= 128+81

= 209

For n=2,

2×42×2+1 + 33×2+1 = 2×45+37

= 2×1024+2187

= 2048+2187

= 4235

Now, the H.C.F of 209 and 4235 is 11.

Hence, λ=11.

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