Answer :

A. Draw the given quadrilateral ABCD.



B. Draw the diagonal AC of quadrilateral ABCD.


C. Draw a parallel line through point D to diagonal AC of quadrilateral ABCD which intersects at E produced BC.


D. DE||AC, ΔABE is the required triangle.



Proof:


∆ACE = ∆ADC (on same base AC and between same parallels AC and DE)


∆ACE = ∆ADC


∆ABC + ∆ADC = ∆ACE + ∆ABC (adding area of ∆ABC on both sides)


quadrilateral ABCD = ∆ABE


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