Q. 44.7( 13 Votes )
A. Draw the given quadrilateral ABCD.
B. Draw the diagonal AC of quadrilateral ABCD.
C. Draw a parallel line through point D to diagonal AC of quadrilateral ABCD which intersects at E produced BC.
D. DE||AC, ΔABE is the required triangle.
∆ACE = ∆ADC (on same base AC and between same parallels AC and DE)
∴ ∆ACE = ∆ADC
∆ABC + ∆ADC = ∆ACE + ∆ABC (adding area of ∆ABC on both sides)
∴ quadrilateral ABCD = ∆ABE
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