Answer :

let the lowest number be , so other numbers are x + 1

And x + 2

According to given conditions 45 < x + (x + 1) + (x + 2) < 54

Solving this equation, we have 45 < 3x + 3 < 54

Adding – 3 on both sides

42 < 3x < 51

Dividing by 3 on both sides

14 < x < 17

So x = 15 or x = 16

So consecutive numbers are 15,16,17 or 16,17,18

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