# Find the equation of the straight line passing through the point (6, 2) and having slope – 3.

Given, A straight line passing through the point (6,2) and the slope is – 3

To Find: The equation of the straight line.

Formula used: The equation of line is [y – y1 = m(x – x1)]

Explanation: Here, The line is passing through (6,2)

The slope of line, m = – 3 (Given)

Coordinates of line are (x1,y1) = (6,2)

The equation of line = y – y1 = m(x – x1)

By putting the values, we get

y – 2 = – 3(x – 6)

y – 2 = – 3x + 18

y + 3x – 20 = 0

Hence, The equation of line is y + 3x – 20 = 0

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