Here chord = 6.6 = 2 × 3.3 cm = 2 × radius, hence PQ is diameter of the circle.
Steps of construction:
i. Draw a circle with center O, and radius 3.3 cm
ii. Draw a diameter PQ passing through center.
iii. Draw AB ⊥ OQ and CD ⊥ OP , such that AB and CD pass through Q and P respectively.
iv. AB and CD are required tangents.
Observation: AB || CD, i.e. tangents at opposite ends of diameter are parallel.
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