Given: base BC= 5.2cm, ∠C = 45° of ΔABC and
perimeter of ΔABC = 10 cm.
Required: To construct a ΔABC
Steps of construction:
i: Draw a segment BC of length of 5.2cm.
ii: At vertex C, construct ∠C = 45° and produce a ray P’C
iii: Mark an arc on ray CP cutting at D such that CD = 4.8cm.
iv: Draw segment DB.
v: Construct the perpendicular bisector of segment DB.
vi: Name the point of intersection of ray CP and the perpendicular bisector of DB as A.
vii: Draw segment AB.
ΔABC is the required triangle.
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