Q. 43.8( 25 Votes )

Construct ΔABC, in which BC= 5.2cm, C = 45° and perimeter of ΔABC is 10 cm.

Answer :

Given: base BC= 5.2cm, C = 45° of ΔABC and

perimeter of ΔABC = 10 cm.


Required: To construct a ΔABC


Steps of construction:


i: Draw a segment BC of length of 5.2cm.



ii: At vertex C, construct C = 45° and produce a ray P’C



iii: Mark an arc on ray CP cutting at D such that CD = 4.8cm.



iv: Draw segment DB.



v: Construct the perpendicular bisector of segment DB.



vi: Name the point of intersection of ray CP and the perpendicular bisector of DB as A.



vii: Draw segment AB.



ΔABC is the required triangle.


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