Q. 45.0( 1 Vote )
Consider the following frequency distribution:
The upper limit of the median class is
To find median class,
Assume Σfi = N = Sum of frequencies,
fi = frequency of class intervals
and Cf = cumulative frequency
Lets convert this data into exclusive type of data.
So, N = 57
⇒ N/2 = 57/2 = 28.5
The cumulative frequency just greater than (N/2 = ) 28.5 is 38, so the corresponding median class is 11.5 - 17.5.
∴ Upper limit of this median class = 17.5
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