Q. 44.2( 79 Votes )

# ∆ AMT ~ ∆ AHE. In ∆ AMT, AM = 6.3 cm, ∠TAM = 50°, AT = 5.6 cm.Construct ∆ AHE.

Answer :

_{Steps of construction:}

i. Draw a triangle AMT, with AM = 6.3 cm, ∠TAM = 50° cm and AT = 5.6 cm, choosing AM as base.

ii. Below AM, draw an acute angle ∠MAX.

iii. Mark four points A_{1}, A_{2}, A_{3}, A_{4}, A_{5}, A_{6} and A_{7} on AX, such that AA_{1} = A_{1}A_{2} =…= A_{6}A_{7} [As ratio is 7:5, we choose 7 points]

iv. Join MA_{7} and Draw HA_{5} || MA_{7}

v. Draw HE || MT

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