Let DE be the pole of 6 m length casting shadow of 3.6 m . Let AB be the tower x meter height casting shadow of 18mat the same time.
Since pole and tower stands vertical to the ground, they form right angled triangle with ground.
Δ ABC and Δ EDF are similar by AA similarity criterion
∴ x/6 = 18 /3.6
⇒ x = 30
The height of the tower is 30 m
Rate this question :