Answer :


Let DE be the pole of 6 m length casting shadow of 3.6 m . Let AB be the tower x meter height casting shadow of 18mat the same time.


Since pole and tower stands vertical to the ground, they form right angled triangle with ground.


Δ ABC and Δ EDF are similar by AA similarity criterion


x/6 = 18 /3.6


x = 30


The height of the tower is 30 m

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