Q. 3 M4.0( 8 Votes )

# Let’s find G.C.D of the following algebraic expression:6x2-13xa + 6a2, 6x2 + 11xa-10a2, 6x2 + 2xa-4a2

Factors of 6x2-13xa + 6a2

=6x2-9xa-4xa + 6a2

=3x(2x-3a)-2a(2x-3a)

= (3x-2a)(2x-3a)

Factors of 6x2 + 11xa-10a2

= 6x2 + 15xa-4xa-10a2

=3x(2x + 5a)-2a(2x + 5a)

=(3x-2a)(2x + 5a)

Factors of 6x2 + 2xa-4a2

=6x2 + 6xa-4xa-4a2

=6x(x + a)-4a(x + a)

=(6x-4a)(x + a)

=2(3x-2a)(x + a)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

the GCD of 6x2-13xa + 6a2, 6x2 + 11xa-10a2, 6x2 + 2xa-4a2is 3x-2a

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