Q. 3 J4.2( 10 Votes )

# Let’s find G.C.D of the following algebraic expression:x3-16x, 2x3 + 9x2 + 4x, 2x3 + x2-28x

Factors of x3-16x

=x(x2-16)

=x(x + 4)(x-4) … (Using a2-b2=(a + b)(a-b))

Factors of 2x3 + 9x2 + 4x

=x(2x2 + 9x + 4)

=x(2x2 + 8x + x + 4)

=x{2x(x + 4) + 1(x + 4)}

=x[{(2x + 1)(x + 4)}]

=x×(2x + 1)×(x + 4)

Factors of 2x3 + x2-28x

=x(2x2 + x-28)

=x(2x2 + 8x-7x-28)

=x{2x(x + 4)-7(x + 4)}

=x[{(2x-7)(x + 4)}]

=x×(2x-7)×(x + 4)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

the GCD of x3-16x, 2x3 + 9x2 + 4x, 2x3 + x2-28x is x(x + 4)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Multiplication of Algebraic Expression40 mins
Division of Algebraic Expressions36 mins
Division of Algebraic Expressions37 mins
Algebraic Expressions and Identities43 mins
Smart Revision | Quiz on Algebraic Expression and Identities44 mins
NCERT | Practice Qs on Addition and Subtraction of Algebraic Expressions42 mins
How to Use Algebraic Identities40 mins
Genius Quiz | Algebraic Expressions and Identities30 mins
Algebric Expressions and Identities45 mins
Operations on Algebraic Expressions51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses