Q. 3 H4.0( 8 Votes )

# Let’s find G.C.D

Factors of 8(x2-4)=2×2×2×(x-2)×(x + 2)

Factors of 12(x3 + 8)

=2×2×3×(x + 2)×(x2-2x + 4)

… ((x3 + 8)= (x + 2)×(x2-2x + 4) from properties)

Factors of 36(x2-3x-10)

Factors of (x2-3x-10)

=(x2-5x + 2x-10)

=x(x-5) + 2(x-5)

=(x + 2)(x-5)

Factors of 36(x2-3x-10)=2×2×3×3×(x + 2)×(x-5)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

the GCD of 8(x2-4),12(x3 + 8),36(x2-3x-10) is 4(x + 2)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Let's find G.C.D.West Bengal - Mathematics

Let's find the G.West Bengal - Mathematics

Let's find the G.West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics

Let’s find G.C.D West Bengal - Mathematics