Q. 3 C4.8( 4 Votes )

# Solve any the thr

Step-1: construct the segment PM having length 5.6 cm and using protractor draw lines at the angles P and M which measures 60° and 70° respectively mark the intersection point as T thus ∆PMT is ready

Step-3: construct perpendicular bisector of line PM by keeping the needle of compass at point P and taking approximately more than half of PM distance in compass draw arc above and below PM

Step-4: keeping the same measurement in compass keep the needle at point M and draw intersecting arcs above and below segment PM

Step-5: join the intersections of arcs to get a line ‘a’ which is perpendicular bisector of segment PM.

Step-6: Similarly by repeating steps 3,4,5 construct a perpendicular bisector for line TM so instead of P substitute T and repeat steps 3,4,5 we will get a line ‘b’ perpendicular bisector of segment TM

Step-7: keep the needle of compass at point of intersection of line a and b and from there take distance till any vertex of triangle PTM and construct the circle

The circle is required circumcircle to ∆PTM

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