Q. 3 C3.5( 12 Votes )

Let’s find G.C.D of the following algebraic expression:2ax(a-x)2, 4a2x(a-x)3

Factors of 2ax(a-x)2=2×a×x×(a-x) ×(a-x)

Factors of 4a2x(a-x)3=2×2×a×a×x×(a-x) ×(a-x) ×(a-x)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

the GCD of 2ax(a-x)2, 4a2x(a-x)3 is 2ax(a-x)2

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