Q. 3 C3.5( 12 Votes )

# Let’s find G.C.D of the following algebraic expression:

2ax(a-x)^{2}, 4a^{2}x(a-x)^{3}

Answer :

Factors of 2ax(a-x)^{2}=2×a×x×(a-x) ×(a-x)

Factors of 4a^{2}x(a-x)^{3}=2×2×a×a×x×(a-x) ×(a-x) ×(a-x)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

∴the GCD of 2ax(a-x)^{2}, 4a^{2}x(a-x)^{3} is 2ax(a-x)^{2}

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