A box of sweets i

Given: number of children (x) = 24

Number of sweets each get (y) = 5

New number of children (x₁) = 24 – 4 = 20

Let new Number of sweets each get = y₁

As per given condition if the number of students reduced then each will get more sweets than previously given. Hence, it is the question of indirect proportion.

i.e. xy = x₁y₁

or 24×5 = 20 × y₁

⇒ y₁ = 6

Hence, each children will get 6 sweets.