Q. 3 A5.0( 3 Votes )

# <span lang="EN-US

Given: A circle with center P. CB tangent and line AC intersect a circle in point D

Construction: Join BD.

To Prove: ADB =90° [Angle inscribed in semicircle]

PBC = 90° [Tangent perpendicular to the radius]

i.e. ABC =90°

In Δ ACB and Δ ABD

ABC = ADB [Each is of 90°]

CAB = DAB [Common angle]

ΔACB ΔABD [AA property]

AP = PB …(radii of the same circle)

AB = AP +PB

AB = 2AP

Substituting value of AB in equation (1)

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