Answer :
The figure of the question is given below:
Given that ∠MPN = 60°
The above figure represents a quadrilateral PNQM
So, the sum of all angles of a quadrilateral is 360°
∴ ∠MQN + ∠QNP + ∠MPN + ∠PMQ = 360° .. eq(1)
Since PM is ⊥ MQ and PN is ⊥ QN
⇒ ∠QNP = ∠PMQ = 90°
By substituting all angles in eqn (1)
∠MQN + 90° + 60° + 90° = 360°
∴ ∠MQN = 120°
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