Answer :

200 m/s

Let, initially plane is at C and after 30 seconds it moves to D. therefore, distance travelled by plane in 30 secs = CD = AE = y m

Let, AB = x m

Height of plane from ground = AC = DE = 3000√3 m

In ∆ABC,

∴ x = 3000 m

Now, in ∆ADE,

∴ 3000 + y = 3000√3 × √3

∴ 3000 + y = 9000

∴ y = 6000 m

Therefore, distance travelled by plane in 30 secs is 6000 m

Therefore, speed of plane is

∴ speed = 200 m/s

Hence, speed of the airplane is 200 m/s.

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