Q. 395.0( 1 Vote )

# In the given figure, AB || DC, ∠BAD = 90°, ∠CBD = 28° and ∠BCE = 65°. Then ∠ABD = ?A. 32°B. 37°C. 43°D. 53°

BCE = ABC =65o (Alternate Angles)

ABC = ABD + DBC

65o = ABD + 28o

ABD = 65 – 28

= 37o

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