Q. 395.0( 1 Vote )

# In the given figure, AB || DC, ∠BAD = 90°, ∠CBD = 28° and ∠BCE = 65°. Then ∠ABD = ?

A. 32°

B. 37°

C. 43°

D. 53°

Answer :

∠BCE = ∠ABC =65^{o} (Alternate Angles)

∠ABC = ∠ABD + ∠DBC

65^{o} = ∠ABD + 28^{o}

∠ABD = 65 – 28

= 37^{o}

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