Answer :

3x + 5y – 15 = 0


5y = 15 – 3x



When, x = 0 then,






y = 3


When, x = 5 then,





y = 0


Plotting (0, 3) and (5, 0) we get the following graph,



The blue line indicates the required graph of 3x + 5y – 15 = 0


Now, to show that (1, 2) is not the solution of


3x + 5y – 15 = 0


We put x = 1 and y = 2 in






Since, LHS ≠ RHS therefore, x = 1, y = 2 is not a solution 3x + 5y – 15 = 0.


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