Q. 384.4( 5 Votes )

# Draw the graph of

Answer :

3x + 5y – 15 = 0

⇒ 5y = 15 – 3x

When, x = 0 then,

⇒ y = 3

When, x = 5 then,

⇒ y = 0

Plotting (0, 3) and (5, 0) we get the following graph,

The blue line indicates the required graph of 3x + 5y – 15 = 0

Now, to show that (1, 2) is not the solution of

3x + 5y – 15 = 0

We put x = 1 and y = 2 in

Since, LHS ≠ RHS therefore, x = 1, y = 2 is not a solution 3x + 5y – 15 = 0.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

The area of the tRS Aggarwal & V Aggarwal - Mathematics

The distance betwRD Sharma - Mathematics

Draw the graph ofRS Aggarwal & V Aggarwal - Mathematics

Draw the graph ofRD Sharma - Mathematics