Answer :

Let the three vertices of rectangle ABCD be A (2, 2), B (-3, 2) and C (-3, 5)

Now, on plotting these points on the graph paper and by joining the points we get:



The point A lies in the first quadrant while B and C lie in the second quadrant


Let us assume D be the fourth vertex of the rectangle


Abscissa of D = Abscissa of A = 2


And, Ordinate of D = Ordinate of C = 3


Hence, Coordinate of the fourth vertex, D = (2, 5)


Let y-axis cut AB and CD at point L and M respectively


AB = (BL + LA)


= (3 + 2)


= 5 units


Also, BC = 5 – 2


= 3 units


Area of rectangle ABCD = BC × AB


= 3 × 5


= 15 square units


Hence, the area of the rectangle ABCD is 15 square units


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