Q. 375.0( 3 Votes )

In a ΔABC its is A. 60°

B. 45°

C. 75°

D. 30°

Answer :

As per question,

So,

∠A = 90^o

∠B = 60^o

∠C = 30^o

∠ACB + ∠ACD + ∠ECD = 180^o (sum of angles on straight line)

∠ECD = 180^o – 90^o – 30^o

= 60^o

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In a ΔABC its is A. 60°B. 45°C. 75°D. 30°