Answer :
Let CD = x m, AB = 75 m
In Δ ACB,
⇒ BC = AB = 75 m
In Δ ADB,
⇒ BD = 75√3
⇒ BC + x = 75√3
⇒ 75 + x = 75√3
⇒ x = 75(√3 – 1) = 54.9 m
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