Answer :

Let the vertices of the triangle be A (1, 4), B (-2, 2) and C (3, 2)


Now, when we plot and join these points on the graph paper, we get a triangle ABC


Let the line BC intersect y-axis at D


BC = BD + DC


= (2 + 3) units


= 5 units


Now, AL is drawn perpendicular to x-axis meeting BC at L


Ordinate of point L = Ordinate of point C – 2


AL = AM – LM


= 4 – 2


= 2 units


Hence, area of =


=


=


= 5 units


Area of the triangle ABC = 5 square units


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