# The three vertice

Let the vertices of the triangle be A (1, 4), B (-2, 2) and C (3, 2) Now, when we plot and join these points on the graph paper, we get a triangle ABC

Let the line BC intersect y-axis at D

BC = BD + DC

= (2 + 3) units

= 5 units

Now, AL is drawn perpendicular to x-axis meeting BC at L

Ordinate of point L = Ordinate of point C – 2

AL = AM – LM

= 4 – 2

= 2 units

Hence, area of = = = = 5 units

Area of the triangle ABC = 5 square units

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