We will use integration by parts.
Here, take f(x) = x2 and g(x) = sin x
⇒ f’(x) = 2x
Substituting these values, we evaluate the integral.
We use integration by parts again.
Here, take f(x) = x and g(x) = cos x
⇒ f’(x) = 1
Using these values in equation for I1
Substituting I1 in I, we get
⇒ I = (0 + π + 0) – (2)
⇒ I = π – 2
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