Q. 354.0( 4 Votes )
It is propo
ABCD is a square lawn of side 58m. AED and BFC are two circular ends.
Now, diagonal of the lawn = √(58)2 + (58)2 = 58√2m
It is given that diagonal of square = Diameter of circle
∴The radius of a circle having a centre at the point of intersection of diagonal
It is given that square ABCD is inscribed by the circle with centre O.
∴Area of 4 segments = Area of circle – Area of square
= πr2 – (side)2
Area of whole lawn = Area of circle – Area of two segments
=5286.28 – 961.14
= 4325.14 m2
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