Q. 354.0( 4 Votes )

It is propo

Answer :


ABCD is a square lawn of side 58m. AED and BFC are two circular ends.


Now, diagonal of the lawn = √(58)2 + (58)2 = 58√2m


It is given that diagonal of square = Diameter of circle


The radius of a circle having a centre at the point of intersection of diagonal



It is given that square ABCD is inscribed by the circle with centre O.


Area of 4 segments = Area of circle – Area of square


= πr2 – (side)2






m2



= 961.14m2


Area of whole lawn = Area of circle – Area of two segments



=5286.28 – 961.14


= 4325.14 m2

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