Q. 355.0( 2 Votes )

In the given figure, AB || CD. If EAB = 50° and ECD = 60°, then AEB = ?


A. 50°

B. 60°

C. 70°

D. 55°

Answer :

AB || CD and BC is traversal.


So, DCB = ABC = 60o


Now in triangle AEB, we have


ABE + BAE + AEB =180o


AEB =180o – 60o – 50o


= 70o

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