Q. 355.0( 2 Votes )
In the given figure, AB || CD. If ∠EAB = 50° and ∠ECD = 60°, then ∠AEB = ?
A. 50°
B. 60°
C. 70°
D. 55°
Answer :
AB || CD and BC is traversal.
So, ∠DCB = ∠ABC = 60o
Now in triangle AEB, we have
∠ABE + ∠BAE + ∠AEB =180o
∠AEB =180o – 60o – 50o
= 70o
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