Q. 345.0( 1 Vote )

Two institutions decided to award their employees for the three values resourcefulness, competence and determination in the from of prizes at the rate of₹x, ₹y and ₹z respectively per person. The first institutions decided to award respectively 4,3 and 2 employees with total prize money of ₹37000 and the second institution decided to award respectively 5,3 and 4 employees with total prize money of ₹47000. If all the three prizes per person together amount to ₹12000, then using matrix method find the value of x,y and z. What values are described in this equations?(CBSE 2013)

Answer :

Let the numbers are x, y, z be the cash awards for Resourcefulness, Competence, and Determination respectively


4x + 3y + 2z = 37000 …… (i)


Also,


5x + 3y + 4z = 47000 …… (ii)


Again,


x + y + z = 12000 …… (iii)



A X = B


|A| = 4(3 – 4) – 3(5 – 4) + 2(5 – 3)


= 4(– 1) – 3(1) + 2(2)


= – 4 – 3 + 4


= – 3


Hence, the unique solution given by x = A – 1B


C11 = (– 1)1 + 1 (3 – 4) = – 1


C12 = (– 1)1 + 2 (5 – 4) = – 1


C13 = (– 1)1 + 3 (5 – 3) = 2


C21 = (– 1)2 + 1 (3 – 2) = – 1


C22 = (– 1)2 + 2 (4 – 2) = 2


C23 = (– 1)2 + 3 (4 – 3 ) = – 1


C31 = (– 1)3 + 1 (12 – 6) = 6


C32 = (– 1)3 + 2 (16 – 10) = – 6


C33 = (– 1)3 + 3 (12 – 15) = – 3


Adj A =


X = A – 1 B =


X =


X =


=


Hence, x = 4000, y = 5000 and z = 3000


Thus, The value X, Y, Z describes the amount of prizes per person for Resourcefulness, Competence and Determination.

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