Mark against the A. 4 units

B. 2 units

C. units

D. units

Given: The equations of the planes are x + 2y – 2z + 1 = 0 and 2x + 4y – 4z – 4z + 5 = 0

To find: distance between the planes

Formula Used: Distance between two parallel planes ax + by + cz + d₁ = 0 and ax₁ + by₁ + cz₁ + d₁ = 0 is

Explanation:

The equations of the planes are:

x + 2y – 2z + 1 = 0 and 2x + 4y – 4z – 4z + 5 = 0

Multiplying the equation of first plane by 2,

2x + 4y – 4z + 2 = 0

Therefore distance between them is

Therefore distance between the planes is units