Q. 34

Mark against the A. 4 units

B. 2 units

C. units

D. units

Answer :

Given: The equations of the planes are x + 2y – 2z + 1 = 0 and 2x + 4y – 4z – 4z + 5 = 0


To find: distance between the planes


Formula Used: Distance between two parallel planes ax + by + cz + d1 = 0 and ax1 + by1 + cz1 + d1 = 0 is



Explanation:


The equations of the planes are:


x + 2y – 2z + 1 = 0 and 2x + 4y – 4z – 4z + 5 = 0


Multiplying the equation of first plane by 2,


2x + 4y – 4z + 2 = 0


Therefore distance between them is





Therefore distance between the planes is units

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