Answer :

Given,

In ΔPQR,


PS bisects QPR and QS = SR


To prove:


PQ = PR



In ΔPQS and ΔPRS


QS = SR [Given]


QPS = RPS [Given]


PS = PS [Common]


ΔPQS is congruent to ΔPRS [S.A.S]


PQ = PR [C.P.C.T.C]


Hence Proved.


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