Q. 344.3( 3 Votes )

Find the area of

Answer :

It is given that A(2, 4), B(2 + , 5) and C(2, 6) are the vertices of the parallelogram ABCD.


Area of the triangle having vertices (x1,y1), (x2,y2) and (x3,y3)


= |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|


Area of □ABCD = 2 × Area of ∆ABC


Area of ∆ABC = |2(5 - 6)+ (2 + )(6 - 4)+2(4 - 5)|


= |-2 + 4 + - 2|


= × = sq. units


Area of □ABCD = 2 × = sq. units


Hence, the area of given parallelogram is sq. units

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