Q. 344.4( 47 Votes )

A TV reporter was

Answer :


Let us prepare table for cumulative frequencies for curve 1 and 2





(i) For curve 1 first cumulative frequency is least and last one is highest. Hence, it less than type ogive. Whereas for curve 2 first cumulative frequency is heighest and last one is least. Hence, it greater than type ogive.


(ii) Calculation of median :


Here, total frequency = fi = N = 66



cumulative frequency just greater than or equal to 33 is 40.


Therefore, corresponding class, 20 -30 is a median class.



Here, L = 20, c.f. = 32, h = 10, f = 8



Median = 20 + 1.25


Median = 21.25


Hence, median rainfall of Dispur is 21.25 cm.


(iii) Mean rainfall = 23.4 cm


We know that,


Mean – Mode = 3 (Mean – Median)


23.4 – Mode = 3 (23.4 – 21.25)


23.4 – Mode = 3 (2.15)


23.4 – Mode = 6.45


Mode = 23.4 – 6.45


Mode = 16.95


Hence, Modal rainfall of Dispur is 16.95 cm.


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