Q. 344.4( 47 Votes )

# A TV reporter was

Answer :

Let us prepare table for cumulative frequencies for curve 1 and 2 (i) For curve 1 first cumulative frequency is least and last one is highest. Hence, it less than type ogive. Whereas for curve 2 first cumulative frequency is heighest and last one is least. Hence, it greater than type ogive.

(ii) Calculation of median :

Here, total frequency = fi = N = 66 cumulative frequency just greater than or equal to 33 is 40.

Therefore, corresponding class, 20 -30 is a median class. Here, L = 20, c.f. = 32, h = 10, f = 8 Median = 20 + 1.25

Median = 21.25

Hence, median rainfall of Dispur is 21.25 cm.

(iii) Mean rainfall = 23.4 cm

We know that,

Mean – Mode = 3 (Mean – Median)

23.4 – Mode = 3 (23.4 – 21.25)

23.4 – Mode = 3 (2.15)

23.4 – Mode = 6.45

Mode = 23.4 – 6.45

Mode = 16.95

Hence, Modal rainfall of Dispur is 16.95 cm.

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