Q. 33

Mark against the A. units

B. 5√3 units

C. units

D. 8√5 units

Answer :

Given: The equations of the parallel planes are 2x – 3y + 6z = 5 and 6x – 9y + 18z + 20 = 0


To find: distance between the planes


Formula Used: Distance between two parallel planes ax + by + cz + d1 = 0 and ax1 + by1 + cz1 + d1 = 0 is



Explanation:


The equations of the parallel planes are:


2x – 3y + 6z – 5 = 0



Therefore distance between them is





Therefore distance between the planes is units

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