Q. 335.0( 2 Votes )

In the given figure, BAC = 40°, ACB = 90° and BED = 100°. Then BDE = ?


A. 50°

B. 30°

C. 40°

D. 25°

Answer :

In triangle AEF,


BED = EFA + EAF


EFA = 100 – 40 = 60o


CFD = EFA (vertical opposite angles)


= 60o


In triangle CFD, we have


CFD + FCD + CDF = 180o


CDF = 180o 90o 60o


= 30o


So, BDE = 30o

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