Q. 335.0( 2 Votes )

# In the given figure, ∠BAC = 40°, ∠ACB = 90° and ∠BED = 100°. Then ∠BDE = ?A. 50°B. 30°C. 40°D. 25°

In triangle AEF,

BED = EFA + EAF

EFA = 100 – 40 = 60o

CFD = EFA (vertical opposite angles)

= 60o

In triangle CFD, we have

CFD + FCD + CDF = 180o

CDF = 180o 90o 60o

= 30o

So, BDE = 30o

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