# In Figure 6, thre

Given: Radius of each circle = 3.5 cm

Join the centers of the three circles. An equilateral triangle of side 7 cm each is formed.

A = B = C = 60° = (π/3) radians

Area of the shaded region = Area of triangle ABC – Area of the three sectors

Area of equilateral triangle = × (Side)2

Area of triangle ABC = × (7)2

= cm2

Area of the sector with central angle A = (1/2) × (A/180) × π × r2

= (1/2) × (60/180) × π × 3.5 × 3.5

=

= 77/12

Area of sector with central angle A = Area of sector with central angle B = Area of sector with central angle C

Area of three sectors = 3 × (77/12)

= 77/4

Thus, Area of the shaded region =

= cm2

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