Q. 325.0( 1 Vote )

# Red queens

Given 2 red queens and 2 black jacks are removed from the pack of 52 playing cards.

Then, remaining number of cards = 52 – 4 = 48

We know that probability of an event E, P (E)

(i) Since 2 red queens are removed, number of red colour cards remaining = 26 – 2 = 24

P (of red colour) = 24/48 = 1/2

(ii) There are only 2 queens remaining.

P (a queen) = 2/48 = 1/24

(iii) There are 4 ace cards.

P (ace) = 4/48 = 1/12

(iv) Since 2 red queens and 2 black jacks are removed, number of face cards remaining = 12 – 4 = 8

P (a face card) = 8/48 = 1/6

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