Q. 325.0( 1 Vote )

In the given figure, BAC = 30°, ABC = 50° and CDE = 40°. Then AED = ?


A. 120°

B. 100°

C. 80°

D. 110°

Answer :

ACB + ABC + BAC =180


ACB = 180 – 50 – 30 = 100o(Sum of angles of triangle is 180)


ACB + ACD = 180 (linear pair of angles)


ACD = 180 – 100 = 80o


In triangle ECD,


ECD + CDE + DEC = 180


DEC = 180 – 80 – 40


= 60o


DEC + AED = 180o(linear pair of angles)


AED = 180o – 60o


= 120o

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