Q. 325.0( 1 Vote )

# In the given figure, ∠BAC = 30°, ∠ABC = 50° and ∠CDE = 40°. Then ∠AED = ?A. 120°B. 100°C. 80°D. 110°

ACB + ABC + BAC =180

ACB = 180 – 50 – 30 = 100o(Sum of angles of triangle is 180)

ACB + ACD = 180 (linear pair of angles)

ACD = 180 – 100 = 80o

In triangle ECD,

ECD + CDE + DEC = 180

DEC = 180 – 80 – 40

= 60o

DEC + AED = 180o(linear pair of angles)

AED = 180o – 60o

= 120o

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