Q. 324.0( 4 Votes )

In the given figure, AD bisects BAC in the ratio 1: 3 and AD = DB. Determine the value of x.


Answer :

Let the ratio be y

DAB = y


DAC = 3y


y + 3y + 108° = 180° [Angle on a straight line]


4y = 72°


y = 18°


DAC = 3y = 54°


ABD = 18° [ AD = DB, ΔABD is an isosceles triangle]


In ΔABC,


x + A + B = 180° [Sum of all angles of a triangle = 180°]


x = 180° - 72° - 18°


x = 90°


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
RD Sharma | Polynomials - I43 mins
NCERT | Triangles-I48 mins
Know Calculation Hacks I46 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses