# In the given figu

In ΔBDC DBC = DCB so

BD = DC …(i)

{sides opposite to equal angles in a triangle are equal}

Now let’s consider that ΔABD and ΔADC –

AB = AC {given}

And BD = DC {from equation (i)}

Hence ΔABD and ΔADC are congruent.

So BAD = DAC (congruency criteria)

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