Answer :

In ΔBDC DBC = DCB so

BD = DC …(i)


{sides opposite to equal angles in a triangle are equal}


Now let’s consider that ΔABD and ΔADC –


AB = AC {given}


AD is a common side.


And BD = DC {from equation (i)}


Hence ΔABD and ΔADC are congruent.


So BAD = DAC (congruency criteria)


Hence AD bisects BAC.


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