Q. 325.0( 7 Votes )

In the given figu

Answer :

In BOP


OB = OP [radii of same circle]


OPB = PBO


[Angles opposite to equal sides are equal]


As, PBO = 30°


OPB = 30°


Now,


OPT = 90°


[Tangents drawn at a point on circle is perpendicular to the radius through point of contact]


BPT = OPB + OPT = 30° + 90° = 120°


Now, In ΔBPT


BPT + PBO + PTB = 180°


120° + 30° + PTB = 180°


PTB = 30°


PTA = PTB = 30°

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