Q. 325.0( 1 Vote )

# Area lying in first quadrant and bounded by the circle x^{2} + y^{2} = 4 and the lines x = 0 and x = 2, is

A. π

B. π/2

C. π/3

D. π/4

Answer :

The part of the circle x^{2} + y^{2} = 4 in between x = 0 and x = 2 is the semicircle to the right of the y – axis.

And the part of this semicircle in the first quadrant is a quadrant of the circle.

So, area A of the portion is basically the area of a quadrant of the circle.

∴ A = πr^{2}/4

= π × 2^{2}/4

= π (Ans)

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