Q. 325.0( 1 Vote )
Area lying in first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2, is
The part of the circle x2 + y2 = 4 in between x = 0 and x = 2 is the semicircle to the right of the y – axis.
And the part of this semicircle in the first quadrant is a quadrant of the circle.
So, area A of the portion is basically the area of a quadrant of the circle.
∴ A = πr2/4
= π × 22/4
= π (Ans)
Rate this question :
Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y.
Using integration, find the area of the triangle ABC, coordinates of whose vertices are A(4, 1), B(6, 6) and C(8, 4).Mathematics - Board Papers
Sketch the graph of y =|x + 3| and evaluate the area under the curve
y =|x + 3| above x-axis and between
x = – 6 to x = 0
Using integration, find the area of the region bounded by the triangle whose vertices are (-1, 2), (1, 5) and (3, 4).Mathematics - Board Papers
Find the area of the region included between the parabola y2 = x and the line
x + y = 2.