Q. 314.2( 5 Votes )

<span lang="EN-US

Answer :

Let the time taken by quicker pipe = x minutes

Then the time taken by slower pipe =(x + 3) minutes


Given that two pipes together fill cistern in minutes.


So,



40(2x + 3)=13x(x + 3)


80x + 120=13x2 + 39x


13x2-41x-120=0


13x2-65x + 24x-120=0


13x(x-5) + 24(x-5)=0


(13x + 24)(x-5)=0


There are two solutions possible: or x=5


As time cannot be a negative value, x=5 minutes.


Time taken by quicker pipe = 5minutes


Time taken by slower pipe = 8minutes


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses