Let the time taken by quicker pipe = x minutes
Then the time taken by slower pipe =(x + 3) minutes
Given that two pipes together fill cistern in minutes.
40(2x + 3)=13x(x + 3)
80x + 120=13x2 + 39x
13x2-65x + 24x-120=0
13x(x-5) + 24(x-5)=0
(13x + 24)(x-5)=0
There are two solutions possible: or x=5
As time cannot be a negative value, x=5 minutes.
Time taken by quicker pipe = 5minutes
Time taken by slower pipe = 8minutes
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