Q. 313.8( 16 Votes )

In figure 4, PQ i

Answer :

Given PQ = 16 cm and PO = 10 cm


We have to find TP.


PR = RQ = 16/2 = 8 cm [Perpendicular from the centre bisects the chord]


In Δ OPR,


OR


= √36 = 6 cm


Let POR be θ.


In Δ POR, tan θ


We know OP TP


[Point of contact of a tangent is perpendicular to the line from the centre]


In Δ OTP, tan θ



TP = 7.5 cm


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