Q. 314.0( 8 Votes )

If cos θ = 2/3 th A. 1

B. 0

C. 3

D. 4

Answer :

Given,


cos θ = 2/3 = b/h = k


2sec2 θ + 2 tan2θ – 7


b = 2k, h = 3k


Untitled31.png


In ∆ABC,


h2 = p2 + b2


(3k)2 = p2 + (2k)2


9k2 = p2 + 4k2


p2 = 9k2 – 4k2


p2 = 5k2


p = 5k


Then,


Sec θ = h/b = 3k/2k = 3/2 and


Tan θ = p/b = √5k/2k = √5/2


2 sec2 θ + 2 tan2 θ – 7





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