Q. 314.0( 8 Votes )

If cos θ = 2/3 th

Answer :

Given,


cos θ = 2/3 = b/h = k


2sec2 θ + 2 tan2θ – 7


b = 2k, h = 3k


Untitled31.png


In ∆ABC,


h2 = p2 + b2


(3k)2 = p2 + (2k)2


9k2 = p2 + 4k2


p2 = 9k2 – 4k2


p2 = 5k2


p = 5k


Then,


Sec θ = h/b = 3k/2k = 3/2 and


Tan θ = p/b = √5k/2k = √5/2


2 sec2 θ + 2 tan2 θ – 7





Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses