# Find four differe

2x + y = 6

y = 6 – 2x

To find four different solutions of the equation, we will put four different values of x.

Let them be, x = 1, x = 2, x = 3 and x = 4.

When, x = 1, then, y = 6 – 2×1

y = 6 – 2

y = 4

Therefore, (x, y) = (1, 4)

When, x = 2, then, y = 6 – 2×2

y = 6 – 4

y = 2

Therefore, (x, y) = (2, 2)

When, x = 3, then, y = 6 – 2×3

y = 6 – 6

y = 0

Therefore, (x, y) = (3, 0)

When, x = 4, then, y = 6 – 2×4

y = 6 – 8

y = – 2

Therefore, (x, y) = (4, – 2)

Hence, the solutions are (1, 4), (2, 2), (3, 0), (4, – 2)

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