Answer :

Given: Height of tower, CD = 15 m


Angle of depression of A from the top of tower,DAC = 60°


Angle of depression of B from the top of tower,DBC = 45°


To find: distance between two points A and B



Lines DE & BC are parallel and DB is the transversal


EDB =DBC [Alternate angles]


So,DBC = 45°


Lines DE & BC are parallel and DB is the transversal


EDA =DAC [Alternate angles]


So,DAC = 60°


In right Δ DCA, we have






Rationalising




x = 5√3 …(i)


In right Δ DCB, we have





[from (i)]


5√3 + y = 15


y = 15 – 5√3


y = 5(3 – √3)


Distance between two points = 5(3 – √3)m


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