Answer :

**Given:** Height of tower, CD = 15 m

Angle of depression of A from the top of tower, ∠DAC = 60°

Angle of depression of B from the top of tower, ∠DBC = 45°

To find: distance between two points A and B

Lines DE & BC are parallel and DB is the transversal

∠EDB = ∠DBC [Alternate angles]

So, ∠DBC = 45°

Lines DE & BC are parallel and DB is the transversal

∠EDA = ∠DAC [Alternate angles]

So, ∠DAC = 60°

In right Δ DCA, we have

Rationalising

⇒ x = 5√3 …(i)

In right Δ DCB, we have

[from (i)]

⇒ 5√3 + y = 15

⇒ y = 15 – 5√3

⇒ y = 5(3 – √3)

∴ Distance between two points = 5(3 – √3)m

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