Q. 305.0( 4 Votes )

The angle of elev

Answer :

We have


Let height of the hill be H m, and distance between the hill and the tower is x m


We shall find value of x first so that we can find H.


In ∆ABC,


[, ]


[, tan 30° = 1/√3]


x = 50√3


Now in ∆DCB,


[, ]


√3 = H/x [, tan 60° = √3]


x√3 = H


√3 × 50√3 = H [, x = 50√3]


H = 50 × 3 = 150


Hence, the height of hill is 150 m.


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