Answer :
We have
Let height of the hill be H m, and distance between the hill and the tower is x m
We shall find value of x first so that we can find H.
In ∆ABC,
[∵, 
]
⇒ 
[∵, tan 30° = 1/√3]
⇒ x = 50√3
Now in ∆DCB,
[∵, 
]
⇒ √3 = H/x [∵, tan 60° = √3]
⇒ x√3 = H
⇒ √3 × 50√3 = H [∵, x = 50√3]
⇒ H = 50 × 3 = 150
Hence, the height of hill is 150 m.
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