Q. 304.0( 22 Votes )

In figure 5, PQRS

Answer :

The figure is given as:



Since the lawn is a square, the sides PQ = QR = SR = SP = 42 m.


Also, let OR = OP = x being the radius of the circle.


Now, the diagonal PR = OR + OP = x + x = 2x.


Applying the Pythagoras theorem in ΔPRQ, we get,


(PR)2 = (RQ)2 + (PQ)2


(2x)2 = (42)2 + (42)2


4x2 = 2× (42)2


x2 = 882


x = √882 = 21√2 m.


Now, Area of the two flower beds = 2× {Area of the segment of circle with centre angle 90°)


Area



A = 2{ 693 – 441} = 504 m2


Area of the flowers beds is 504 m2


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