Answer :

The figure is given as:

Since the lawn is a square, ∴ the sides PQ = QR = SR = SP = 42 m.

Also, let OR = OP = x being the radius of the circle.

Now, the diagonal PR = OR + OP = x + x = 2x.

Applying the Pythagoras theorem in ΔPRQ, we get,

(PR)^{2} = (RQ)^{2} + (PQ)^{2}

⇒ (2x)^{2} = (42)^{2} + (42)^{2}

⇒ 4x^{2} = 2× (42)^{2}

⇒ x^{2} = 882

⇒ x = √882 = 21√2 m.

Now, Area of the two flower beds = 2× {Area of the segment of circle with centre angle 90°)

⇒ Area

⇒

⇒ A = 2{ 693 – 441} = 504 m^{2}

∴ Area of the flowers beds is 504 m^{2}

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Glimpses of India39 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation