In figure 5, PQRS

The figure is given as:

Since the lawn is a square, ∴ the sides PQ = QR = SR = SP = 42 m.

Also, let OR = OP = x being the radius of the circle.

Now, the diagonal PR = OR + OP = x + x = 2x.

Applying the Pythagoras theorem in ΔPRQ, we get,

(PR)² = (RQ)² + (PQ)²

⇒ (2x)² = (42)² + (42)²

⇒ 4x² = 2× (42)²

⇒ x² = 882

⇒ x = √882 = 21√2 m.

Now, Area of the two flower beds = 2× {Area of the segment of circle with centre angle 90°)

⇒ Area

⇒

⇒ A = 2{ 693 – 441} = 504 m²

∴ Area of the flowers beds is 504 m²