# In Fig. 4, ABCD i

On the basis of given conditions in the question the figure can be drawn as follows:

It is given in the question that,

As the radius of all the semi-circles is same

Area of 4 semi-circles = AOB + DOC + AOD + BOC

We know that, Area of semi-circle =

Area of 4 semi–circles =

= 4 × 77

= 308 cm2

Also we know that, area of Square = (Side)2

Area of square, ABCD = 14 × 14

= 196 cm2

Hence, Area of shaded region = 2 (Area of square) – 4 (Area of semi-circle)

= 2 × 196 – 308

= 392 – 308

= 84 cm2

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